meresponses/lastidep 25441649+04 myCherryCreek Projectile Lab - Inlo... my.cherrycreekscho... Cantidy, Leah Physics Lab - New Healthy Glow L. Sale - Imperative -17 Points) DETAILS The displacement of a particle at t = 0.350 s is given by the expression x = (3.00 m) cos(6.00xt), where x is in meters and is in seconds (a) Determine the frequency and period of

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Question

meresponses/lastidep 25441649+04 myCherryCreek Projectile Lab - Inlo... my.cherrycreekscho... Cantidy, Leah Physics Lab - New Healthy Glow L. Sale - Imperative -17 Points) DETAILS The displacement of a particle at t = 0.350 s is given by the expression x = (3.00 m) cos(6.00xt), where x is in meters and is in seconds (a) Determine the frequency and period of the motion Hz s (b) Determine the amplitude of the motion m (c) Determine the displacement of the particle at t = 0.350 s. m (d) At what time after t=0 does it first reach equillibrium? (e) At what time after t=0 does it reach zero velocity for the first time? (f)What total distance does it travel during the first period?

Expert Answer

$And\nexpression of partide x=(3.000) (QSL6.000+)\ncomparing with\nthe standerd equation\nX = A COSC20ft +0.)\nwe have\n0\n@) 20ft: 6$

$Ans (c)\nat\nnext t = 0.350 SX\nx = (3.00) COS (6.00 n X(0.35+0.35))\nx = 2.427 m\n1 X\nx = 2.43 m An\nd) For the equilibrium\nx 20 c$ $t = 5x1 ~.35\n12\nt = 0.0666 Second A\n$